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Error probability across independent tests

For m independent true-null tests with exact rejection probability a, the chance of at least one rejection is 1 − (1 − a)^m.

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Define a family of error events

Let E_i be a false rejection for test i. In this exercise every null is true, each event has probability a, and the error events are independent. These are stronger assumptions than merely using the same reported significance level in a spreadsheet.

Calculate no errors before taking the complement

The chance of no error for one test is 1 − a. Under independence, multiply that chance m times for no errors across the family. Subtract from one for at least one error.

P(V≥1)=1−(1−a)mP(V\ge1)=1-(1-a)^m

V is the number of false rejections; all m nulls are true and their rejection events are independent with probability a.

Compare probability with expected count

The expected count is ma by linearity of expectation. It does not require independence when each event probability equals a. A count can exceed one; a probability cannot.

Illustration with a = 0.05
mAt least one error under independenceExpected count
10.050.05
100.40126310.5
200.64151411

Do not erase dependence or conservative tests

If each test has error probability at most alpha, exact equality need not hold. If error events are dependent, the product step need not hold. A general union bound instead limits the family probability by the sum of the individual probabilities, capped at one.

Further references