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Specify an independent finite-variance model
Each synthetic observation is one with probability 0.001 and zero otherwise. The observations are independent and share that distribution. Their mean is 0.001 and variance is 0.001 × 0.999. This model meets the classical finite-variance conditions.
Calculate the mass at zero
Let K count events in thirty observations. The sample mean is K/30, and P(K = 0) = 0.999^30 ≈ 0.9704309673. Thus nearly all samples have mean zero, with remaining outcomes at positive multiples of 1/30. The distribution is discrete and strongly asymmetric at this n.
| K | Sample mean | Probability |
|---|---|---|
| 0 | 0 | 0.97043097 |
| 1 | 0.03333333333333333 | 0.029142071 |
| 2 | 0.06666666666666667 | 0.00042298301 |
| 3 | 0.1 | 0.0000039517933 |
Inspect the complete count distribution
All count values zero through thirty are included. Most probability lies at zero; the small positive outcomes are not evenly balanced by negative outcomes because the count cannot be negative. A normal curve at n = 30 would not reproduce this mass pattern.
Exact binomial probabilities for a fictional event probability of 0.001; all counts from zero to thirty are included. This is an illustrative example.
View the chart values
| Series | Event count | Probability |
|---|---|---|
| Exact probability | 0 | 0.97043097 |
| Exact probability | 1 | 0.029142071 |
| Exact probability | 2 | 0.00042298301 |
| Exact probability | 3 | 0.0000039517933 |
| Exact probability | 4 | 2.6701306E-8 |
| Exact probability | 5 | 1.3898578E-10 |
| Exact probability | 6 | 5.7968709E-13 |
| Exact probability | 7 | 1.9894881E-15 |
| Exact probability | 8 | 5.7255037E-18 |
| Exact probability | 9 | 1.4009685E-20 |
| Exact probability | 10 | 2.9449789E-23 |
| Exact probability | 11 | 5.359867E-26 |
| Exact probability | 12 | 8.494951E-29 |
| Exact probability | 13 | 1.1774014E-31 |
| Exact probability | 14 | 1.4311328E-34 |
| Exact probability | 15 | 1.5280697E-37 |
| Exact probability | 16 | 1.4339994E-40 |
| Exact probability | 17 | 1.1821228E-43 |
| Exact probability | 18 | 8.5460996E-47 |
| Exact probability | 19 | 5.4029395E-50 |
| Exact probability | 20 | 2.9745913E-53 |
| Exact probability | 21 | 1.41789E-56 |
| Exact probability | 22 | 5.8062652E-60 |
| Exact probability | 23 | 2.0215921E-63 |
| Exact probability | 24 | 5.9022124E-67 |
| Exact probability | 25 | 1.4179489E-70 |
| Exact probability | 26 | 2.7295544E-74 |
| Exact probability | 27 | 4.0478322E-78 |
| Exact probability | 28 | 4.3413044E-82 |
| Exact probability | 29 | 2.997E-86 |
| Exact probability | 30 | 1E-90 |
Separate this finite sample from the limit
The standardized mean approaches normality as n grows for this fixed model. That limit does not certify approximation quality at thirty. A report should assess the actual model and approximation needed for its task rather than declaring any thirty observations normal.