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Scenario variance and squared deviation from a target

Probabilities of 30%, 50% and 20% with returns of −2%, 8% and 14% imply a mean of 6.2% and variance of 33.96 in squared percentage-point units.

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Calculate the mean implied by the distribution

The expected return is 0.30×(−2%) + 0.50×8% + 0.20×14% = 6.2%. A separately stated value of 6% does not become the mean of this distribution merely because it is described that way.

Compute deviations from 6.2%

Using percentage-number returns, the deviations are −8.2, 1.8 and 7.8. Square them and apply the supplied probabilities.

Probability-weighted variance contributions
ReturnProbabilitySquared deviation from 6.2Weighted contribution
−2%30%67.2420.172
8%50%3.241.620
14%20%60.8412.168
Total100%33.960

Explain the calculation around a 6% target

Using 6% as the reference instead gives a probability-weighted squared deviation of 34. This is a valid mean squared deviation from that specified target, but it is not the model variance. The difference is the squared gap between mean and target: (6.2 − 6)² = 0.04. Thus 33.96 + 0.04 = 34.

Take the square root in matching units

The square root of the actual variance is approximately 5.8275%. Dividing the weighted variance by three would add an inappropriate extra divisor. Dividing an unweighted sum by three would instead describe an equal-weight model.

Further references